Search Results
Note: Block B, also referred as final block (FB), and class in the MadWeight world. Description inspired by MadWeight.
This block corresponds to an initial state with Bjorken fractions q_1 and q_2, and a final state with a visible particle with momenta p_2, and an invisible particle with momenta p_1, both coming from a resonance with mass s_{12}. Extra radiation (ISR) it is also allowed.
The goal of this Block is to address the change of variables needed to pass from the standard phase-space parametrization to the \frac{1}{4\pi E_1} ds_{12} \times J parametrization. Per integration point in CUBA, this Block outputs the value of the jacobian, J, and the four momenta of the invisible particle, p_1. The system of equations needed to compute p_1 is described below.
Change of variables
From the standard phase-space parametrisation:
dq_1 dq_2\frac{d^3 p_1}{(2\pi)^3 2E_1}(2\pi)^4 \delta^4 (P_{in}-P_{out})
where P_{in} and P_{out} are the total four-momenta in the initial and final states, to the following parametrisation:
\frac{1}{4\pi E_1} ds_{12} \times J
where the jacobian, J, is given by:
J = \frac{E_1}{s} \left| p_{2z} E_1 - E_2 p_{1z} \right|^{-1}
Parameters
- Collision energy.
Inputs
- Visible particle, with 4-momentum p_2
- The invariant s_{12} as output from the Flatter or NarrowWidthApproximation module.
Outputs
- Invisible particle, with 4-momentum p_1 (up to two solutions possible)
- Jacobian, one per solution.
System of equations to compute p_1
The integrator throws random points in the invariant ( s_{12}) while p_2 is a known quantity. The equations to compute p_1 are:
\begin{eqnarray} s_{12} &=& (p_1 + p_2)^2 = M_{1}^{2} + M_{2}^2 + 2 E_1 E_2 + 2 p_{1x}p_{2x} + 2p_{1y}p_{2y} + p_{1z}p_{2z} \\ p_{1x} &=& - p_{Tx} \\ p_{1y} &=& - p_{Ty} \\ p_1^2 &=& 0 \Leftrightarrow E_{1}^2 = p_{1x}^2 + p_{1y}^2 + p_{1z}^2 \end{eqnarray}
Where \vec{p}_T is the total transverse momentum of the visible particles. Using the values of p_{1x}, p_{1y} from equations (2) and (3), equation (1) can be written as p_{1z} = A - B E_1, where A and B are:
\begin{eqnarray} A &=& \frac{s_{12} - M_{2}^2 + 2(p_{Tx}p_{2x} + p_{Ty}p_{2y})}{2 p_{2z}} \\ B &=& \frac{E_2}{p_{2z}} \\ \end{eqnarray}
Finally equation (4) can be written as (1 - B) E_{1}^2 + 2AB E_1 - C = 0, where C = p_{Tx}^{2} + p_{Ty}^{2}.
Each solution of the quadratic equation with a positive value of E_1 is taken.